Loading docs/math/mobius.md +1 −1 Original line number Diff line number Diff line Loading @@ -488,7 +488,7 @@ $$ 于是有 $$ \operatorname g(p_j^{k+1})=g(p_j^k)+p_j^{2k+1}\cdot(p_j-1) \operatorname g(p_j^{k+1})=\operatorname g(p_j^k)+p_j^{2k+1}\cdot(p_j-1) $$ 那么，对于线性筛中的 $\operatorname g(i\cdot p_j)(p_j|i)$ ，令 $i=a\cdot p_j^w(\operatorname{gcd}(a,p_j)=1)$ ，可得 Loading Loading
docs/math/mobius.md +1 −1 Original line number Diff line number Diff line Loading @@ -488,7 +488,7 @@ $$ 于是有 $$ \operatorname g(p_j^{k+1})=g(p_j^k)+p_j^{2k+1}\cdot(p_j-1) \operatorname g(p_j^{k+1})=\operatorname g(p_j^k)+p_j^{2k+1}\cdot(p_j-1) $$ 那么，对于线性筛中的 $\operatorname g(i\cdot p_j)(p_j|i)$ ，令 $i=a\cdot p_j^w(\operatorname{gcd}(a,p_j)=1)$ ，可得 Loading
Early <lin_erli@outlook.com>Early <lin_erli@outlook.com>