sched/topology: Simplify build_overlap_sched_groups()
Now that the first group will always be the previous domain of this @cpu this can be simplified. In fact, writing the code now removed should've been a big clue I was doing it wrong :/ Signed-off-by:Peter Zijlstra (Intel) <peterz@infradead.org> Cc: Linus Torvalds <torvalds@linux-foundation.org> Cc: Mike Galbraith <efault@gmx.de> Cc: Peter Zijlstra <peterz@infradead.org> Cc: Thomas Gleixner <tglx@linutronix.de> Cc: linux-kernel@vger.kernel.org Signed-off-by:
Ingo Molnar <mingo@kernel.org>
parent
0372dd27
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