Commit 99c7f878 authored Feb 15, 2012 by Gerd Hoffmann Committed by Anthony Liguori Feb 17, 2012

input: send kbd+mouse events only to running guests.



Trying to interact with a stopped guest will queue up the events,
then send them all at once when the guest continues running, with
a high chance to have them cause unwanted actions.

Avoid that by only injecting the input events only when the guest
is in running state.

Signed-off-by: Gerd Hoffmann <kraxel@redhat.com>
Signed-off-by: Anthony Liguori <aliguori@us.ibm.com>

parent aa24822b

input.c

+6 −0

Original line number	Diff line number	Diff line
		@@ -130,6 +130,9 @@ void qemu_remove_led_event_handler(QEMUPutLEDEntry *entry)

		void kbd_put_keycode(int keycode)
		{
		if (!runstate_is_running()) {
		return;
		}
		if (qemu_put_kbd_event) {
		qemu_put_kbd_event(qemu_put_kbd_event_opaque, keycode);
		}
		@@ -151,6 +154,9 @@ void kbd_mouse_event(int dx, int dy, int dz, int buttons_state)
		void *mouse_event_opaque;
		int width, height;

		if (!runstate_is_running()) {
		return;
		}
		if (QTAILQ_EMPTY(&mouse_handlers)) {
		return;
		}