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The previous formuation with multiple assignments to __typeof(*hptr) falls down when hptr is qualified const. E.g. with const struct S *p, p->f is also qualified const. With this formulation, there's no assignment to any local variable. Signed-off-by:Richard Henderson <rth@twiddle.net> Signed-off-by:
Blue Swirl <blauwirbel@gmail.com>