slub: Prepare __slab_free() for unfrozen partial slab out of node partial list

Now the partially empty slub will be frozen when taken out of node partial
list, so the __slab_free() will know from "was_frozen" that the partially
empty slab is not on node partial list and is a cpu or cpu partial slab
of some cpu.

But we will change this, make partial slabs leave the node partial list
with unfrozen state, so we need to change __slab_free() to use the new
slab_test_node_partial() we just introduced.

Signed-off-by: Chengming Zhou <zhouchengming@bytedance.com>
Reviewed-by: Vlastimil Babka <vbabka@suse.cz>
Tested-by: Hyeonggon Yoo <42.hyeyoo@gmail.com>
Reviewed-by: Hyeonggon Yoo <42.hyeyoo@gmail.com>
Signed-off-by: Vlastimil Babka <vbabka@suse.cz>